Question

if the points A(4,3) and B(x,5) are on the circle with centre O(2,3) then find the value of x

Answer 1

X
x = 2
SO B 2,5
O : centre

Answer 2

Answer:

Here point A, B is on the circle with centre O.

Hence OA and OB are radius.

So, OA=OB. Hence OA² = OB²

By using distance formula

OA²= ( (4-2)² + (3-3)²) = 4 +0 =4

OB²= ( (2-x)² + (5-3)²)= 4 - 2x +x² +4 = x² - 2x +8

BUT OA²=OB²

4 = x² - 2x + 8

x² - 2x + 4 = 0

D²=(b²-4ac)

D²=( (-2)² - 4(1)(4)) = - 12

Here D² is negative

So, D²<0 So, no real roots are possible.

Step-by-step explanation: