Question

If the points A(4,3) and B(x, 5) lie on the circle with centre 0(2, 3), find the value of x.
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Answer 1

Solution :-

→ (4 - 2)² + (3 - 3)² = (x - 2)² + (5 - 3)²

→ (2)² + (0)² = x² - 4x + 4 + (2)²

→ 4 = x² - 4x + 8

→ x² - 4x + 8 - 4 = 0

→ x² - 4x - 4 = 0

→ x² - 2x - 2x + 4 = 0

→ x(x - 2) - 2(x - 2) = 0

→ (x - 2)(x - 2) = 0

→ (x - 2)² = 0

→ x = 2

Answer 2

Answer:0(2,3) is the centre of the circle .coordinates of a(4,3) and b(x,5).

by mid point formula: x=x1+x2/2 and y=y1+y2/2.

2= x+4/2

x+4=4

x=0

hence coordinates of b are (0,5)

Step-by-step explanation: