If the points A(6,1), B(8,2), C(9,4), &D (P,3) are the vertices of a parallelogram, taken in order, find the value of 'p'
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Hello good morning and here is your answer
By using distance formula,
take two points B(8,2) and D(p,3)
distance formula is √(x₂-x₁)²+(y₂-y₁)²
in point B 8 is x₁ and 2 is y₁
in point D p is x₂ and 3 is y₂
Now,
=√(p-3)²+(3-2)²
=√(p-8)²+(1)²
=p-8+1
=p-7
⇒p=7
Hope this cleared your doubt....
#BE BRAINLY ☺
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