If the points A (6,1) B(8, 2)
c (9,4) and D (P, 3) are
vertices of a parallelogram, taken
in order Find the value of p
C (9,4)
D (P,3)
A (6, 1)
B (8,2)
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★Given:-
- The points A (6,1) B(8, 2) C(9,4) and D (P, 3) are vertices of a parallelogram, taken in order.
★To find:-
- Value of p.
★Solution:-
✦Diagonals of a parallelogram bisect each other.
Hence,coordinates of the mid-point of diagonal AC are same as the coordinates of the mid-point of diagonal BD.
Using the mid-point formula,
✦(x,y) = [(x₁+x₂)/2, (y₁+y₂)/2]
Where,
- (x,y) = coordinates of the midpoint
- (x₁, y₁)=coordinates of the first point
- (x₂, y₂)=coordinates of the second point
Midpoint of AC:-
→(x,y) = [(x₁+x₂)/2, (y₁+y₂)/2]
→(6+9)/2 , (1+4)/2
→15/2 , 5/2
Midpoint of BD:-
→(x,y) = [(x₁+x₂)/2, (y₁+y₂)/2]
→(8+p)/2 , (2+3)/2
→(8+p)/2 , 5/2
We have the condition:
Coordinates of the mid-point of diagonal AC are same as the coordinates of the mid-point of diagonal BD.
Therefore,
→(8+p)/2 , 5/2 = 15/2 , 5/2
→(8+p)/2 = 15/2
→8+p = 15
→p = 15 - 8
→p = 7
Therefore,the value of p is 7.
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