If the points P(1,2), Q(0,0) and R(a,b) are collinear, then (A) a=b (B) a=2b (C) 2a=b (D) a= - b
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value of area of a triangle =0 for 3 collinear pts
so 1/2(1*(0-b)+0*(b-2)+a*(2-0))=0
0r -b+2a=0
or 2a=b
hence (c) is the correct option
so 1/2(1*(0-b)+0*(b-2)+a*(2-0))=0
0r -b+2a=0
or 2a=b
hence (c) is the correct option
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