If the points p(x,y) is equidistant from l( 5,1) and m(-1,5) find the relationship between xand y
Answers
Answered by
64
Given, pl=pm(equidistant)
squaring on both sides
(pl)^2=(pm)^2
(x-5)^2+(y-1)^2=(-1-x)^2+(5-y)^2
x2+25-10x+y2+1-2y=1+x2+2x+25+y2-10y
12x-8y=0
3x-2y=0
The relationship between x and y is 3x-2y=0.
squaring on both sides
(pl)^2=(pm)^2
(x-5)^2+(y-1)^2=(-1-x)^2+(5-y)^2
x2+25-10x+y2+1-2y=1+x2+2x+25+y2-10y
12x-8y=0
3x-2y=0
The relationship between x and y is 3x-2y=0.
Answered by
4
Step-by-step explanation:
follow above answer
3x-2y=0
3x=2y ..
relationship between xand y is 3x=2y
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