If the points (x,y) is equidistant from the points (m+n,n-m) and (n+m ,m+n) find n
Answers
Answer:
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Given : points (x,y) is equidistant from the points (m+n,n-m) and (n+m , m+n)
To find : n
Solution:
points (x,y) is equidistant from the points (m+n,n-m) and (n+m , m+n)
=> ( m + n - x)² + ( n - m - y)² = (n + m - x)² + (m + n - y)²
=> ( m + n - x)² + ( (n - y) - m)² = (m + n - x)² + ( (n - y) + m)²
Cancelling ( m + n - x)² from both sides
=> ( (n - y) - m)² = ( (n - y) + m)²
=> (n - y)² + m² - 2m(n-y) = (n - y)² + m² + 2m(n-y)
cancelling (n - y)² + m² from both sides
=> - 2m(n-y) = + 2m(n-y)
Dividing by 2m on both sides
=> -(n- y) = n - y
=> - n + y = n - y
=> 2n = 2y
=> n = y
n = y
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