Question

if the polynaomialp[x]=x^-x+1 is divided by [x-2]then the remainder is

Answer 1

Heya ✋

Let see your answer !!!!

$let \: p(x) = x ^{2} - x - 1 \\ g(x) = (x - 2) \\ = > x - 2 = 0 \\ = > x = 2 \\ p(2) = 2 ^{2} - 2 - 1 \\ = 4 - 3 \\ = 1$
Hence , the remainder is 1.







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Answer 2

HEYA...✌✌✌✌✌

HERE IS YOUR ANSWER

The remainder is 3