Question

if the polynomial 2x^3 + kx^2 + 3x-5 and x^3 + x^2 -2x +2k leave same remainder when divided by x-3, find k​

Answer 1

Answer:

Step-by-step explanation:

let

p(x)=2x³+kx²+3x-5

f(x)=x³+x²-2x+2k

g(x)=x-3

now

p(3)=2×(3)³+k×(3)²+3×3-5

     =2×27+9k+9-5

     =54+9k+4

     =9k+58

f(3)=(3)³+(3)²-2×3+2k

    =27+9-6+2k

    =30+2k

A.T.Q.

9k+58=30+2k

9k-2k=30-58

7k=-28

k=-4