If the polynomial 6x⁴+8x³+17x²+21x+7 is divided by 3x²+4x+1 remainder comes to ax+b find the value of a and b
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Answer:
Step-by-step explanation:
Given: If the expression 6 x^{4}+8 x^{3}+17 x^{2}+21 x+7 is ‘divided another one’ 3 x^{2}+4 x+1, ‘remainder’ will be “(ax + b)”.
Thus, the division of both the ‘equations’ are derived in below attached image.
Therefore, \mathrm{x}+2=\mathrm{ax}+\mathrm{b}
\begin{aligned} \mathrm{x} &=\mathrm{ax} \\ \frac{x}{x} &=a \end{aligned}
a = 1 and b = 2
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