If the polynomial f(x)=px³+4x²+3x-4 and g(x)=x³-4x+p are divided by x-3 ,then the remainder in each case is the same,find the value of p.
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Here's your answer mate
lets take F(x)= 3 .....
than for p first equation = Second equation
that is
px^3 +4x^2 +3x-4= x^3 -4x+p
27p+36+9-4=27-12+p
27p+41=15+p
27p-p=15-41
26p= -26
p= -26/26 = -1
Value of p is -1
Hope it Helps!
lets take F(x)= 3 .....
than for p first equation = Second equation
that is
px^3 +4x^2 +3x-4= x^3 -4x+p
27p+36+9-4=27-12+p
27p+41=15+p
27p-p=15-41
26p= -26
p= -26/26 = -1
Value of p is -1
Hope it Helps!
TiwariVaishnavi:
Thanks
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