if the polynomial k x cube + 3 x square minus 8 and 3 x cube minus 5 x + K leave the same remainder when divided by X + 2 then find the value of k
Answers
Answered by
37
hope this helps you out
Attachments:
Answered by
43
This is the answer.
Hope it helps all.
x = -2
P(x) =kx^3 + 3x^2 - 8
P(-2) =k(-2) ^3 + 3(-2) ^2 - 8
= -8k + 12 - 8
= -8k + 4 ____ 1
P(x) = 3x^3 - 5x + k
P(-2) = 3(-2) - 5(-2) + k
= (-24) + 10 + k
= -14 + k_____2
From _1 and _2, we get
-8k + 4 = -14 + k
-8k - k = -14 - 4
-9k = -18
( - and - gets cancel)
9k = 18
Therefore, k= 18/ 9
Hence, k= 2
Similar questions