Question

If the polynomial p(x)=x4-2x3++3x2-ax+8is divided by(x-2)it leaves the remainder 10 . find the vlaue of a

Answer 1

$x - 2 = 0 \\ x = 2$
$x {}^{4} + 2x ^{3} + 3x ^{2} - ax + 8 = 10$
$2 ^{4} - 2 \times 2 ^{3} - 3 \times 2 ^{2} - 2a + 8 = 10 \\ 16 - 16 + 12 - 2a + 8 = 10 \\ - 2a = - 10 \\ a = 5$

Answer 2

${x}^{4} - 2 {x}^{3} + 3 {x}^{2} - ax + 8$
x-2=0
x=2
2^4-2(2)^3+3(2)^2-a(2)+8=10
16-16+12-2a+8=10
0+20-2a=10
-2a=10-20
-2a=-10
2a=10(minus gets cancelled)
a=10/2
a=5
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