Math, asked by pavithra1315, 1 year ago

if the polynomial x cube + 4 x square + 3 x minus 4 and x cube minus 4 x + a lunar same remainder when divided by x minus 3 find the value of a​

Answers

Answered by nbnidhi2582004
1

Answer = 53

Explaination is pinned with it

Hope it will help u

Plz mark me as brainliest

Attachments:
Answered by khushirai31
0

Answer:

a=53

Step-by-step explanation:

when

x-3 = 0

x = +3

since x^3 + 4x^2 + 3x - 4 and

x^3 - 4x + a leaves same remainder

Therefore

x^3 + 4x^2 + 3x - 4 = x^3 - 4x + a

where x = 3

(3)^3 + 4(3)^2 + 3(3) - 4 = (3)^3 - 4(3) + a

27 + 36 + 9 - 4 = 27 - 12 + a

63 + 5 = 15 + a

take the variable on the left hand side of the equals to....and the digits on the right hand side of the equals to (**note the sign will change when you exchange the digits or variables on the other side of equals to)

-a = 15 - 63 - 5

-a = 10 - 63

-a = - 53

negative signs on both the sides gets cancelled...we get...

a = 53

........i hope it helped..

Similar questions