if the polynomial x cube + 4 x square + 3 x minus 4 and x cube minus 4 x + a lunar same remainder when divided by x minus 3 find the value of a
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Answer = 53
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Answer:
a=53
Step-by-step explanation:
when
x-3 = 0
x = +3
since x^3 + 4x^2 + 3x - 4 and
x^3 - 4x + a leaves same remainder
Therefore
x^3 + 4x^2 + 3x - 4 = x^3 - 4x + a
where x = 3
(3)^3 + 4(3)^2 + 3(3) - 4 = (3)^3 - 4(3) + a
27 + 36 + 9 - 4 = 27 - 12 + a
63 + 5 = 15 + a
take the variable on the left hand side of the equals to....and the digits on the right hand side of the equals to (**note the sign will change when you exchange the digits or variables on the other side of equals to)
-a = 15 - 63 - 5
-a = 10 - 63
-a = - 53
negative signs on both the sides gets cancelled...we get...
a = 53
........i hope it helped..
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