Question

If the polynomials 2x + ar? + 3x - 5 and x + x2 - 4x + a leave the same remainder
when divided by X-2, find the value of a.​

Answer 1

According to the Question:

2x+a² +3x -5 = x + x² - 4x + a

(x-2=0 => x=2)

2×2 + a² + 3×2 -5 = 2 + 2² - 4×2 + a

4 + a² + 6 -5 = 2 + 4 - 8 + a

a² - a + 4 + 6 - 5 - 2 - 4 + 8

a² - a + 6