If the polynomials 2x³ + ax² + 3x -5 and x³+ x² - 4x + a leave the same remainder when divided by x - 2, find the value of a.
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Answered by
7
Step-by-step explanation:
We know that remainder is same
in both situations .
So , at x = 2
2(2)³ + a(2)² + 3(2) - 5 = (2)³ + (2)² - 4(2) + a
2(8) + a(4) + 6 - 5 = 8 + 4 - 8 + a
16 + 4a + 1 = 4 + a
4a + 17 = 4 + a
3a = -13
a = -13/3
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11
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