Question

If the polynomials ax³+4x²+3x-4 and x³-4x+a leave the sane remainder when divided by x-3,then find a.Also find the remainder in each case

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Answer 1

Step-by-step explanation:

Hope it's helpful to you

Answer 2

Answer:

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Step-by-step explanation:

let f (x)=ax^3+4x^2+3x-4

and let g (x)=x^3-4x+a

zero of the poynomial of x-3 is 3

according to problem,

f (3)=g (3)

a (3)^3+4 (3)^2+3 (3)-4=27-4 (3)+a

27a+36+9-4=27-12+a

27a+41=15+a

27a-a=15-41

26a= -26

a= -26/26

a= -1