If the polynomials ay³ + 4y²+ 3y – 4 and y³ - 4y + a leave the same remainder when divided by (y -3) find the value of a. please write steps
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p(x) =ay³ + 4y²+ 3y – 4
g(x)=y -3
so, y-3=0
y =3
= a ( 3) ³+ 4(3) +3(3)-4
= 27a+12+9-4
= 27a +17 answer
p(x)=y³ - 4y + a
=(3)³+4(3)-a
= 27 -a+12
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