Question

If the polynomials px^3 +4x² + 3x-4 and x-4x+p are divided by (x-3), then the remainder in
each case is the same. Find the value of p.​

Answer 1

Answer:

hope this helps

Step-by-step explanation:

x-3 = 0

x = 3

px^3 + 4x^2 + 3x -4

p(3)^3 + 4(3)^2 + 3(3) -4

p27 + 36 + 9 -4

p27 + 41 = 0

p27 = -41

therefore, p = -41/27