If the position of a body
is x= 3t+ 5t² then find
the average
velocity?
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Explanation:
Given displacement x=5+3t+2t2
Differentiating the above equation with respect to time t we get velocity of the body
v=dtdx=3+4t
Now again differentiating the velocity with respect to time we get acceleration
a=dtdv=4
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