Question

if the position vector of one end of the line segment AB be 2I+3j-k and the position vector of its middle point be 3(i+j+k) then the position vector of the other end is
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Answer 1

Explanation:

Correct option is

C

3

A=i+j−k and B=2i−j+k

∴AB=(2i−j+k)−(i+j−k)=i−2j+2k

∴∣AB∣=

1

2+(−2) 229 = =3Option C is correct.