Question

If the potential difference is 240 V and the electric current is 10 A ,then power of the electric appliance is​

Answer 1

Answer:

Here, Power of the electric appliance is 2.4Kw

Explanation:

Here, As given in our question,

=Potential difference(V) across the electric appliance=240v

=Electric current(I) dissipated in the electric appliance=10A

So, Power(P) =V×I

=P=240×10

=P=2400watts or 2.4Kw

So, Power of the electric appliance is 2.4Kw.

Thank you.