Question

If the potential difference used to accelerate electron is doubled by what factor does the De Broglie wavelength of the electron beam change

Answer 1

Hey dear,

◆ Answer-
λ' = λ/√2

● Explanation-
De Broglie's wavelength is related to voltage applied as -
λ = h / p
λ = h / √(2meV)

When V is doubled,
λ' = h / √(2me2V)
λ' = h / √(4meV)

From (1) & (2),
λ' = λ/√2

Therefore, De Broglie's wavelength is λ/√2 when voltage is doubled.

Hope this helps you...

Answer 2

Answer:

0.25kv

Explanation:

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