Chemistry, asked by akashdz123, 10 months ago

If the potential energy of the hydrogen electron is -3.02eV then which excited leavel is present?

Answers

Answered by dattahari09

6

Answer: n = 3

Explanation:

Total energy = potential energy/2

TE = 3.02/2 =1.51

TE= 13.6 z2/n2

1.51 =13.6 Z2/n2

Z = 1

n2 =13.6/1.51 =9

n =3

dattahari09: n=3 means. 2 nd excited state

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