If the pressure at half the depth of a lake is equal to two third of a pressure at the bottom of the
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Depth = d
Atmospheric Pressure = P₀ = 10⁵ Pa
Density of water at 4°C (ρ) = 10³ kg/m³
Pressure at half of depth
P = P₀ + (d/2)ρg
P = P₀ + 0.5dρg
Pressure at the bottom of lake
P’ = P₀ + dρg
Given that P = 2P’/3
P₀ + 0.5dρg = 2(P₀ + dρg)/3
P₀ + 0.5dg = 2P₀/3 + 2dρg/3
P₀/3 = dρg/6
d = 2P₀ / (ρg)
d = (2 × 10⁵ Pa) / (10³ kg/m³ × 10 m/s²)
d = 20 m
Depth of lake is 20 m
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इट इज द प्रेजेंट हाफ ऑफ द डेट ऑफ लेक इस इक्वल टू टू थर्ड आफ ऑपरेशन एंड द बॉटम ऑफ एक्सीलरेशन ड्यू टो ग्रेविटी ❄️
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