If the pressure of N2/H2 mixture in a closed apparatus is 100 atm and 20% of the mixture reacts then the pressure at the same temperature would be
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Solution: - (B) 90 N2 + 3 H2⟶ 2 NH3 From the above reaction, 4 mole of reactant produces 2 mole of NH3 Therefore, 20 % mixture reacts to form 10 % NH3
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