Question

if the prime factorization of a rational number and is 2 power 4 into 3 power 4 into 5 power 3 into 7th write the number of consecutive 0 in n

Answer 1

N=2^3×3^4×5^4×7

N=2^3×3^4×5^3×5×7

N=(2×5)^3×3^4×5×7

N=(10)^3×3^5×7

N=3^4×5×7×1000

Therefore ,n gives a natural no.

Since there are 3 zeroes