If the prime factorization of natural number (n) is 2square*3square*5square*7. How many conservative zeroes will it have at the end of it? Jestify your answer
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Solution:
First, the natural number whose prime factorization is 2x2x3x3x5x5x7 = 6300.
Therefore, we can se that only two zeroes are at the end of the natural number.
First, the natural number whose prime factorization is 2x2x3x3x5x5x7 = 6300.
Therefore, we can se that only two zeroes are at the end of the natural number.
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