if the primeter of rhombus is 100 cm and length of one daigonal is 48 cm what is the area of the quadrilateral
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perimeter of rhombus = 4× side = 100
side = 100/4 = 25
In Triangle DOB
DB= side = 25
DO = Diagonal/2 = 48/2 = 24
So OB= √ DB^2 - DO^2 = √25^2 - 24^2
= √625 -576 = √49 = 7
So Area of DOB = 1/2 × DO × OB
= 1/2 × 24 × 7
= 84
Area of quadrilateral = 4× 84 = 336 cm^2
side = 100/4 = 25
In Triangle DOB
DB= side = 25
DO = Diagonal/2 = 48/2 = 24
So OB= √ DB^2 - DO^2 = √25^2 - 24^2
= √625 -576 = √49 = 7
So Area of DOB = 1/2 × DO × OB
= 1/2 × 24 × 7
= 84
Area of quadrilateral = 4× 84 = 336 cm^2
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litlove:
thank u so much
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