Question

if the probability of winning chess game is 1/3 more than twice of probability of losing the match. find the probability of winning and losing the match.

Answer 1

Let the probability of loosing the game be x. The probability of winning the game =2x+1/3=(6x+1)/3 Probabilty of occurence +probability of non occurrence=1 Therefore, x+(6x+1)/3=1 ~(3x+6x+1)/3=1 ~9x+1=3 ~9x=2 ~x=2/9 Therefore probability of loosing =2/9 ||probability of winning=2/9×2+1/3 =(4+3)/9=7/9