If the product of 3 consecutive integers is 120, then the sum of the integers is
A) 9
B) 12
C) 14
D) 15
Answers
Answered by
0
Answer:
answer is 15
let the three consecutive integers be: (x-1),(x),(x+1)
given: product of three consecutive integers is 120.
(x-1)(x)(x+1)=120
(x) (x^2-1)=120
(x^3-x)=120
x^3-x-120=0
x=5(by solving the equation)
so, three consecutive integers are= (x-1)=5-1=4
(x)=5
(x+1)=5+1=6
sum of these three consecutive integers=4+5+6= 15
Answered by
0
Step-by-step explanation:
120:2*2*2*3*5
(2*2)*5*(2*3)
4*5*6
Then the sun of the integers
4+5+6=15
I hope you will be satisfied
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