Question

If the product of the roots of the equation x^2-3kx+2e^2 log k-1=0 is 17 then k=​

Answer 1

Answer:

$given \: products \: of \: the \: equation \: is17 \\ 2e ^{2 log(k - 1) } = 17 \ \\ log(17 \div 2) = 2 log(k - 1 ) \\ 17 \div 2 = (k - 1) ^{2} \\ 6.5 = k^{2} + 1 - 2k \\ k ^{2} - 2k - 5.5 = 0 \\ 2 { k}^{2} - 4k - 11 = 0$

by solving the problem we can get k value