Question

if the product of the zeroes of a quadratic polynomial is -15 and one of the zeroes is 3 .Find the quadratic polynomial
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Answer 1

Answer:

$x^{2} -2x-15$

Step-by-step explanation:

let A&B be the roots of p(x)

AB =   -15

let A = 3

B= -5

A+B= -2

hence p(x)=$x^{2} +(A+B)x+AB$

Answer 2

Answer:

let α and β be the zeros of the polynomial

α= 3

αβ= -5

3×β= -15

β = -15/3

β = -5

so α+β= 3+(-5)

= 3-5 = -2

so the polynomial is

x²-(α+β)x+αβ

x²-(-2)x+(-15)

x²+2x-15

hope it will help you