Question

if the product of the zeroes of the polynomial f(x)=[m+1]x^2 +(2m+3)x - 3m+4 is 2.then find the sum of zeroes .

Answer 1

Product of zeroes = 2
$\frac{-3m+4}{m+1} = 2$
-3m + 4 = 2m + 2
5m = 2
   m = $\frac{2}{5}$

Sum of zeroes = -[$\frac{2m+3}{m+1}$]
                         =- [$\frac{2\frac{2}{5}+3}{\frac{2}{5}+1}$]
                         =  $\frac{-19}{7}$

Sum of zeroes = $\frac{-16}{7}$