Question

If the product of the zeroes of x^2 - 3kx + 2k^2 - 1 is 7, then values of k .​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

let the root be a and b , then

ab = 2k^2-1

3k = 2k^2-1

2k^2 - 3k+1 =0

after solving ,

k= 1 , 1/2