Math, asked by arvindsahai2, 1 month ago

If the product of the zeroes of x^2 - 3kx + 2k^2 - 1 is 7, then values of k .

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Answered by ryuks980809

2

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Step-by-step explanation:

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Answered by infopriyanka1505

0

let the root be a and b , then

ab = 2k^2-1

3k = 2k^2-1

2k^2 - 3k+1 =0

after solving ,

k= 1 , 1/2

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