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Here's the answer buddy mark me brainliest and follow me
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Step-by-step explanation:
1.= (2a)∧3-(b)∧3-3(2a)(b)(2a-b)
=(2a-b)∧3
2.= (3)∧3-(5a)∧3-3(3)(5a)(3-5a)
=(3-5a)∧3
3. (1)∧3-(8a)∧3-3(1)(8a)(1-8a)
=(1-8a)∧3
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