Math, asked by VijayaLaxmiMehra1, 1 year ago

If the product of zeroes of the polynomial ax^2-6x-6 is 4, find the value of 'a'.

Answers

Answered by Panzer786
7
Heya !!!


P(X) = AX²-6X-6


Here,



A = A , B = -6 and C = -6




Product of zeroes = C/A


Alpha × Beta = -6/A


It is given that the product of zeroes is 4.


Therefore,




Alpha × Beta = -6/A


4 = -6/A


4A = -6




A = -6/4



A = -3/2




HOPE IT WILL HELP YOU...... :-)




RehanAhmadXLX: :-)
RehanAhmadXLX: ö.
Answered by RehanAhmadXLX
8
Hey !!

Here is your answer.

Given :
ax² - 6x -6

Here,
a = a, b = -6 and c = -6
Product of zeroes = 4

We know that,
Product of zeroes = c/a
So, c/a = 4
-6/a = 4
a = -6/4 = -3/2

Hope You Got It
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