If the product of zeroes of the polynomial ax^2-6x-6 is 4, find the value of 'a'.
Answers
Answered by
7
Heya !!!
P(X) = AX²-6X-6
Here,
A = A , B = -6 and C = -6
Product of zeroes = C/A
Alpha × Beta = -6/A
It is given that the product of zeroes is 4.
Therefore,
Alpha × Beta = -6/A
4 = -6/A
4A = -6
A = -6/4
A = -3/2
HOPE IT WILL HELP YOU...... :-)
P(X) = AX²-6X-6
Here,
A = A , B = -6 and C = -6
Product of zeroes = C/A
Alpha × Beta = -6/A
It is given that the product of zeroes is 4.
Therefore,
Alpha × Beta = -6/A
4 = -6/A
4A = -6
A = -6/4
A = -3/2
HOPE IT WILL HELP YOU...... :-)
RehanAhmadXLX:
:-)
Answered by
8
Hey !!
Here is your answer.
Given :
ax² - 6x -6
Here,
a = a, b = -6 and c = -6
Product of zeroes = 4
We know that,
Product of zeroes = c/a
So, c/a = 4
-6/a = 4
a = -6/4 = -3/2
Hope You Got It
Here is your answer.
Given :
ax² - 6x -6
Here,
a = a, b = -6 and c = -6
Product of zeroes = 4
We know that,
Product of zeroes = c/a
So, c/a = 4
-6/a = 4
a = -6/4 = -3/2
Hope You Got It
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