Question

If the product of zeroes of the quadratic polynomial p(x) = (k -2) x2 -4x + 1 is 3, write the value of k.​

Answer 1

Answer:

The value of k is :-

$= \dfrac{7}{3}$

Explanation:

Given polynomial,

$\rm \implies \: {(k - 2)x}^{2} - 4x + 1$

On comapring with the general form of equation ax² + bx + c

We get,

• a = (k - 2)
• b = 4
• c = 1

We know,

$\rm \bullet \: product \: of \: zeros = \dfrac{c}{a}$

But, the product of zeros is 3 (given)

$\rm \therefore \: 3 = \dfrac{1}{(k - 2)}$

On solving further,

$\rm \implies \: 3 = \dfrac{1}{(k - 2)}$

$\rm \implies \: 3( k - 2)= 1$

$\rm \implies \: 3k - 6= 1$

$\rm \implies \: 3k = 1 + 6$

$\rm \implies \: 3k = 7$

$\rm \implies \: k = \dfrac{7}{3}$

${\underline{\sf{ \therefore The \: value \: of \: k \: is \: \dfrac{7}{3}}}}$