Math, asked by msmanish4747, 11 months ago

if the product of zeroes of the quardiatic polynomial f(x)=x2+4x+k is 3 find the value of k​

Answers

Answered by itzshrutiBasrani
0

Answer:

Solution :

P(x) = (k-2)x² -4x +k

Given that product of zeroes =3

We know that product of zeroes of polynomial =c/a

Here ,

a= (k-2)

b= -4

and c = k

So

c/a =3

\rightarrow \frac{k}{k - 2} = 3→k−2k=3

→k=3(k-2)

→k= 3k -6

→6 =3k-k

→6 =2k

→6/2 =k

→3 = k

Hence the value of k is 3 .

Answered by bhagirathbhuiya371
0

Answer:

your answer is given below.just have a look.

Step-by-step explanation:

Let a and b be the zeros of the given polynomial.

then,

ab = constant term / coefficient of X2

3 = k/1

k = 3

Hence, k = 3

I hopes it may help u.

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