if the product of zeroes of the quardiatic polynomial f(x)=x2+4x+k is 3 find the value of k
Answers
Answered by
0
Answer:
Solution :
P(x) = (k-2)x² -4x +k
Given that product of zeroes =3
We know that product of zeroes of polynomial =c/a
Here ,
a= (k-2)
b= -4
and c = k
So
c/a =3
\rightarrow \frac{k}{k - 2} = 3→k−2k=3
→k=3(k-2)
→k= 3k -6
→6 =3k-k
→6 =2k
→6/2 =k
→3 = k
Hence the value of k is 3 .
Answered by
0
Answer:
your answer is given below.just have a look.
Step-by-step explanation:
Let a and b be the zeros of the given polynomial.
then,
ab = constant term / coefficient of X2
3 = k/1
k = 3
Hence, k = 3
I hopes it may help u.
Similar questions