Question

If the product of zeros if polynomial 3x^2+10x+2c is 10 then find the value of 'c'​

Answer 1

Answer:

$c = 15$

Step-by-step explanation:

$3 {x}^{2} + 10x + 2c =0$

$here \: \: a = 3 \: \: \: \: b = 10 \: \: \: \: c = 2c$

$let \: the \: roots \: of \: given \: equation \: be \: \\ \alpha \: and \: \beta$

$\alpha \times \beta = 10$

$\frac{c}{a} = 10$

$\frac{2c}{3} = 10$

$c = \frac{10 \times 3}{2}$

$c = 5 \times 3$

$c = 15$