Question

if the product of zeros of the polynomial 3 X square + 5 x + K is 6 find the value of k​

Answer 1

Answer:

let x=1

3x^2+5x+k=6

3×1^2+5×1+k=6

3+5+k=6

8+k=6

k= 6-8

k = -2

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Answer 2

Answer:

18

Step-by-step explanation:

Given :

p ( x ) = 3 x² + 5 x + k

Product of zeroes i.e. α β = 6

We're asked to find value of 'k' :

We know :

Product of zeroes = c / a

= > α β = c / a

= > 6 = k / 3

= > k = 18

Therefore , value of k is 18 :

Additional one :

Let find out zeroes :

= > 3 x² + 5 x + 18

= > x = ( - b ± √ ( b² - 4 a c ) ) / 2 a

= > x = ( - 5 ± √ ( 5² - 4 × 3 × 18 ) ) / 2 × 3

= > x = ( - 5 ± √ - 191 ) / 6

= >  x = ( - 5 ± i √ 191 ) / 6

# The attachment of graph can't be like that since zeroes are not real also cannot be plot of real number line!

Hence we get zeroes as well!