Question

If the product of zeros of the polynomial f(x) = ax³ –6x² + 11x – 6 is 4, then a =
A. 3/2
B. -3/2
C. 2/3
D. -2/3

Answer 1

Step-by-step explanation:

$\sf a {x}^{3} - 6 {x}^{2} + 11x - 6 = 0$

$\sf a {4}^{3} - 6 {4}^{2} + 11 ×4 - 6 = 0$

$\sf 64a - 96 + 11 - 6 = 0$

$\sf 64a = 91$

$\sf a = \frac {91}{64}$

THANKS!!!