Question

If the product of zeros of the polynomial x² - 9x + a is 8, then its zeros are ?​

Answer 1

Answer:

Step-by-step explanation:

Given : If the product of zeros of polynomial  is 8.

To find : The value of a ?

Solution :

The quadratic equation is of form  with roots  and .

The product of roots is  

Here,

Product of roots is  

a=1,b=-9 and c=a

Substitute,

8=a/1

a=8

Step-by-step explanation:

Answer 2

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Given :

→ Product of zeros of the polynomial x²- 9x + a = 8.

To Find :

→ Zeroes of the given polynomial.

Solution :

Comparing x² - 9x + a = 0 with ax² + bx + c = 0, we get,

→ a = 1

→ b = (-9)

→ c = a

So,

→ Product of zeroes = (c/a)

Putting the values,

→ a/1 = 8

→ a = 8

Now, Given Quadratic Equation is x²- 9x + a = 8,

→ x² - 9x + 8 = 0

Splitting the middle terms,

→ x² - 8x - x + 8 = 0

→ x(x - 8) - 1(x - 8) = 0

→ (x - 8) (x - 1) = 0

→ x = 8 & 1.

∴ The zeroes of the given polynomial is 8 & 1.

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