Question

if the product of zeros of this equation ax^2-7x-3is-18than find a​

Answer 1

Answer:

a=-1/6

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Step-by-step explanation:

In a quadratic equation, ax²+bx+c=0

Product of roots=c/a

Here, c=-3 and we have to find 'a'

Product of zeroes= -3/a

18= -3/a

a=-3/18

a=-1/6