If the pts. A(-2,1),B(a,b) and C(4,1) are collinear and a-b= 1,find a and b
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if a-b=1
so,a=1+b .........(1)
now
1/2[(-2)(b-1)+(a)(1-1)+(4)(1-b)]=0
1/2[-2b+2+a-a+4-4b]=0
1/2(-6b+6+0)=0
-6b+6=0×2
-6b+6=0
-6b=-6
b=1
put the value of b in equation(1)
a=1+b
a=1+1
a=2
hence the value if a is 2 and b is 1
so,a=1+b .........(1)
now
1/2[(-2)(b-1)+(a)(1-1)+(4)(1-b)]=0
1/2[-2b+2+a-a+4-4b]=0
1/2(-6b+6+0)=0
-6b+6=0×2
-6b+6=0
-6b=-6
b=1
put the value of b in equation(1)
a=1+b
a=1+1
a=2
hence the value if a is 2 and b is 1
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