subtract =3x+4y-2zfrom the sum of 3+4z +3y-x and 3x +2y -3z + 3
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the answer is 6+3z+y-x
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addition : 4z + 3y - x + 3 + 3x + 2y - 3z + 3
=> z + 5y + 2x + 6
subtraction :- z + 5y + 2x + 6 - ( 3x + 4y - 2z)
=> z + 5y + 2x + 6 - 3x - 4y + 2z
= 3z + y - x + 6
=> z + 5y + 2x + 6
subtraction :- z + 5y + 2x + 6 - ( 3x + 4y - 2z)
=> z + 5y + 2x + 6 - 3x - 4y + 2z
= 3z + y - x + 6
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