Question

If the Q.E. 2x² +kx +8=0 has equal roots then the value of k is .... *​

Answer 1

Answer:

k=4 my friend

Step-by-step explanation:

here the condition is, b^2-4ac=o for roots are equal

k^2-4*2*8=0

k^2-64=0

k^2=64

k=+8 or -8

K is constant so let's take k=8

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