if the quadratic eqution bx2-4bx+2b+1=0 has repeated root then find the value of b
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heya!!!
For repeated roots Descrimnant (D) must be = 0
D = ( -4b )² - 4 ( b ) ( 2b + 1 )
D = 0
16b² -8b² - 4b = 0
8b² - 4b = 0
b ( 8b - 4 ) = 0
b = 0 or b = 1/2
HAVE A NYC DAY!
For repeated roots Descrimnant (D) must be = 0
D = ( -4b )² - 4 ( b ) ( 2b + 1 )
D = 0
16b² -8b² - 4b = 0
8b² - 4b = 0
b ( 8b - 4 ) = 0
b = 0 or b = 1/2
HAVE A NYC DAY!
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