Question

if the quadratic expression x^2+(a-4)x+(a+4) is a perfect square then a=​

Answer 1

$\textbf{Given:}$

$\textsf{Expression is}\;\mathsf{x^2+(a-4)x+(a+4)}$

$\textbf{To find:}$

$\textsf{The value of a}$

$\textbf{Solution:}$

$\textsf{Since the expression}\;\mathsf{x^2+(a-4)x+(a+4)}\;\textsf{is a perfect square,}$

$\textsf{it has equal roots}$

$\mathsf{Then,\;b^2-4ac=0}$

$\mathsf{(a-4)^2-4{\times}1{\times}(a+4)=0}$

$\mathsf{(a-4)^2-4(a+4)=0}$

$\mathsf{a^2+16-8a-4a-16=0}$

$\mathsf{a^2-12a=0}$

$\mathsf{a(a-12)=0}$

$\implies\boxed{\mathsf{a=0,\;12}}$

$\textbf{Find more:}$

If x^2-bx/ax-c =m-1/m+1

has roots which are numerically equal but of opposite sign, then the value of'm'must be

(A) a-b/a+b

(B) a+b/a-b

(C) O

(D) 1

soneone please answer this

https://brainly.in/question/9525569