Question

Two dice are rolled.If the first die shows an even number what is the probability that the sum is more than 9

Answer 1

Answer:

The conditions are that the forst dice shows an even number.(i.e. 2,4,6)

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Sample Space: <4,6> , <6,4> , <6,5> , <6,6>

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PROBABILITY = NO.OF POSSIBLE OUTCOMES/TOTAL NO. OF OUTCOMES

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PROB = 4/36

          =1/9

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therefore: probability is 1/9

Step-by-step explanation:

Answer 2

sample space: { (1,1)......................(6,6)}
n(s): 36

event A: first die is even sum is more than 9

A: { (4,6);(6,4);(6,5);(6,6)}
n(A): 4

p(A) = n(A)/n(s)
= 4/36
=1/9
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